0.00002x^2+0.0203x-5.09=0

Solution for 0.00002x^2+0.0203x-5.09=0 equation:

0.00002x^2+0.0203x-5.09=0

a = 0.00002; b = 0.0203; c = -5.09;
Δ = b2-4ac
Δ = 0.02032-4·0.00002·(-5.09)
Δ = 0.00081929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0203)-\sqrt{0.00081929}}{2*0.00002}=\frac{-0.0203-\sqrt{0.00081929}}{5.8731273138362}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0203)+\sqrt{0.00081929}}{2*0.00002}=\frac{-0.0203+\sqrt{0.00081929}}{5.8731273138362}
$